Chapter 5 - Discrete Probability Distributions - 5-3 Binomial Probability Distributions - Page 219: 18

0.94208

Using the Binomial Probability table the probability is: $P(X<3)=P(X=0)+P(X=1)+P(X=2)={5\choose 0} \cdot (0.2)^0\cdot (0.8)^5+{5\choose 1} \cdot (0.2)^1\cdot (0.8)^4+{5\choose 2} \cdot (0.2)^2\cdot (0.8)^3=0.32768+0.4096+0.2048=0.94208.$