Essentials of Statistics (5th Edition)

Published by Pearson
ISBN 10: 0-32192-459-2
ISBN 13: 978-0-32192-459-9

Chapter 4 - Probability - Review - Review Exercises - Page 188: 15

Answer

$\frac{1}{5,245,786}$

Work Step by Step

Because the order is not important, we can use the combination rule to determine the number of possibilities: $\frac{ 42!}{(42-6)!6!}=5,245,786$. We also know that $probability=\frac{number \ of \ good \ outcomes}{number\ of\ all\ outcomes}$, therefore $P=\frac{1}{5,245,786}$.
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