Answer
$\frac{1}{22,957,480}$
Work Step by Step
Because the order is not important, we can use the combination rule to determine the number of possibilities: $\frac{53!}{(53-6)!6!}=22,957,480$.
We also know that $probability=\frac{number \ of \ good \ outcomes}{number\ of\ all\ outcomes}$, therefore $P=\frac{1}{22,957,480}$.