Essentials of Statistics (5th Edition)

Published by Pearson
ISBN 10: 0-32192-459-2
ISBN 13: 978-0-32192-459-9

Chapter 4 - Probability - 4-6 Counting - Page 180: 9

Answer

$17,383,860$

Work Step by Step

Because the order is not important, we can use the combination rule to determine the number of possibilities: $\frac{27!}{(27-12)!12!}=17,383,860$.
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