Essentials of Statistics (5th Edition)

Published by Pearson
ISBN 10: 0-32192-459-2
ISBN 13: 978-0-32192-459-9

Chapter 3 - Statistics for Describing, Exploring, and Comparing Data - 3-3 Measures of Variation - Page 108: 18

Answer

Variance:16.46 Standard deviation:4.06. Range:16.

Work Step by Step

The mean can be counted by summing all the data and dividing it by the number of data: $\frac{11+3+0−2+3−2−2+5−2+7+2+4+1+8+1+0−5+2}{18}=1.89$: $\mu=1.89.$ Variance=$\frac{\sum (x-\mu)^2}{n}=\frac{(11-1.89)^2+(3-1.89)^2+...+(2-1.89)^2}{18}=16.46.$ Standard deviation=$\sqrt{variance}=\sqrt{16.46}=4.06.$ Range=maximum value-minimum value=$11-(-5)=16$.
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