Essentials of Statistics (5th Edition)

Published by Pearson
ISBN 10: 0-32192-459-2
ISBN 13: 978-0-32192-459-9

Chapter 3 - Statistics for Describing, Exploring, and Comparing Data - 3-3 Measures of Variation - Page 108: 16

Answer

Variance:0.18. Standard deviation:0.423 Range:1.17.

Work Step by Step

The mean can be counted by summing all the data and dividing it by the number of data: $\frac{0.38+0.55+1.54+1.55+0.5+0.6+0.92+0.96+1+0.86+1.46}{11}=0.9382.$ $\mu=0.9382.$ Variance=$\frac{\sum (x-\mu)^2}{n}=\frac{(0.38-0.9382)^2+(0.55-0.9382)^2+...+(1.46-0.9382)^2}{11}=0.18.$ Standard deviation=$\sqrt{variance}=\sqrt{0.18}=0.423$ Range=maximum value-minimum value=$1.55-0.38=1.17$.
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