Answer
Variance:0.18. Standard deviation:0.423 Range:1.17.
Work Step by Step
The mean can be counted by summing all the data and dividing it by the number of data: $\frac{0.38+0.55+1.54+1.55+0.5+0.6+0.92+0.96+1+0.86+1.46}{11}=0.9382.$ $\mu=0.9382.$ Variance=$\frac{\sum (x-\mu)^2}{n}=\frac{(0.38-0.9382)^2+(0.55-0.9382)^2+...+(1.46-0.9382)^2}{11}=0.18.$ Standard deviation=$\sqrt{variance}=\sqrt{0.18}=0.423$ Range=maximum value-minimum value=$1.55-0.38=1.17$.