Essentials of Statistics (5th Edition)

Published by Pearson
ISBN 10: 0-32192-459-2
ISBN 13: 978-0-32192-459-9

Chapter 11 - Chi-Square and Analysis of Variance - 11-2 Goodness-of-Fit - Page 544: 6

Answer

Fail to reject the null hypothesis.

Work Step by Step

The value of the test statistic: $X^2=6.6$. By using the table, the corresponding P-value: P=0.679. If the P-value is less than the significance level, then this means the rejection of the null hypothesis. Hence:P is more than $\alpha=0.05$, hence we fail to reject the null hypothesis. Hence we can say that there is sufficient evidence to support that the last digits don't occur with the same frequency.
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