Elementary Statistics: Picturing the World (6th Edition)

Published by Pearson
ISBN 10: 0321911210
ISBN 13: 978-0-32191-121-6

Chapter 6 - Confidence Intervals - Section 6.1 Confidence Intervals for the Mean - Exercises - Page 307: 42

Answer

143.52 < $\mu$ < 156.48$ The CI is wider in this question.

Work Step by Step

Formula for CI $\bar{x}$ $\pm$ ( z$\times$$\frac{\sigma}{\sqrt n}$) =$150 \pm ( 2.5758\times\frac{19.50}{\sqrt60 })$ = $150\pm 6.484$ CI: $143.516 < \mu < 156.484 \approx 143.52 < \mu < 156.48$ The CI is wider in this question. This is because the higher standard deviation indicates that there is more variability in this population.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.