Answer
Margin of Error $\approx$ 1.861
Work Step by Step
The z score that corresponds to the confidence level 0.95 is 1.96.
Using z = 1.96, $\sigma$ = 5.2, n = 30 , margin of Error is given by:
z x $\frac{\sigma}{\sqrt n}$
1.96 x $\frac{5.2}{\sqrt 30}$
$\approx$ 1.861
