Answer
(a) z ≈ 1.15
(b) An age of 32 is about 1.15 standard deviations above
the mean.
(c) Not unusual
Work Step by Step
z = (x - μ) / σ = (32-28.1) / 3.4 = 1.15
Usual values have z score in the range -2 and 2.
Elementary Statistics: Picturing the World (6th Edition)
by Larson, Ron; Farber, Betsy
Published by
Pearson
ISBN 10:
0321911210
ISBN 13:
978-0-32191-121-6
Chapter 2 - Descriptive Statistics - Section 2.5 Measures of Position - Exercises - Page 112: 41
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