Answer
a. P(Fiction)=$1/2$
b. P(not a children’s nonfiction)=$10/13$,
c. P(adult or children’s nonfiction)=$8/13$
Work Step by Step
Total number of books is 260
a. Fiction, total friction books=260-70-60=130, P(Fiction)=$130/260=1/2$
b. Not a children’s nonfiction book, P(children’s nonfiction)=$60/260=3/13$,
P(not a children’s nonfiction)=$1-3/13=10/13$,
c. An adult book or a children’s nonfiction book,
P(adult or children’s nonfiction)=$\frac{100+60}{260}=8/13$
