Answer
Fail to reject the null hypothesis.
Work Step by Step
$H_{0}:\sigma_1=\sigma_2,$ $H_{a}:\sigma_1\ne \sigma_2$. :$F=\frac{s_1^2}{s_2^2}=\frac{5.9^2}{5.48^2}=1.159.$ The critical values by the table with df=min(34,35)=34: $f_{0.025}$ is between 1.8752 and 2.0739. the corresponding probability using the table, hence P=0.1081070292. If the value of the test statistic is in the rejection region, reject the null hypothesis. 1.159 is less than 1.8752, hence we fail to reject the null hypothesis. The background colour doesn't seem to have effect on the variation.
