Answer
Reject the null hypothesis.
Work Step by Step
$H_{0}:\mu_d=0,$ $H_{a}:\mu_d\ne0$. The test statistic is:$t=\frac{\overline{d}-\mu_d}{s_d/\sqrt{n}}=\frac{-8.2439-0}{13.4427/\sqrt{82}}=-5.553.$ The P is the corresponding probability using the table with df=82-1=81, hence P is less than 0.01. If the P-value is less than $\alpha$, which is the significance level, then this means the rejection of the null hypothesis. Hence:P is less than $\alpha=0.05$, hence we reject the null hypothesis. Hence there seems to be a difference in age.