Answer
Reject the null hypothesis.
Work Step by Step
We first find the value of z using a ti-84 calculator. To do this, press "Stat," and then select "1-PropZTest." Then, plug in $p_0=0.795$, $x=44$, and $n=48$. Then, select $\ne p_0$, and press enter. Doing this, we see that $z=2.088$.
Using a table of z-scores, we find:
$P=1−0.9817+0.0183=0.0366$
$0.0366\lt0.05$, hence we reject the null hypothesis.
