Elementary Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321836960
ISBN 13: 978-0-32183-696-0

Chapter 7 - Estimates and Sample Sizes - Review - Cumulative Review Exercises: 4

Answer

33

Work Step by Step

$\alpha=1-0.95=0.5.$ Using the table: $z_{\alpha/2}=z_{0.025}=1.96.$ Hence the sample size:$\left (\frac{z_{\alpha/2}\cdot \sigma}{E}\right)^2=\left (\frac{1.96\cdot 5.8}{2}\right)^2\approx33$.
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