Elementary Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321836960
ISBN 13: 978-0-32183-696-0

Chapter 6 - Normal Probability Distributions - Review - Chapter Quick Quiz - Page 315: 10

Answer

82.31%.

Work Step by Step

$z_{1}=\frac{value-mean}{standard \ deviation}=\frac{4.2-4.577}{0.382}=-0.99$ $z_{2}=\frac{value-mean}{standard \ deviation}=\frac{5.4-4.577}{0.382}=2.15$ Using the table, the probability of z being between -0.99 and 2.15 is equal to the probability of z being less than 2.15 minus the probability of z being less than -0.99, which is: 0.9842-0.1611=0.8231=82.31%.
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