Elementary Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321836960
ISBN 13: 978-0-32183-696-0

Chapter 6 - Normal Probability Distributions - 6-3 Applications of Normal Distributions - Basic Skills and Concepts: 31

Answer

$P_{1}=17.94, P_{2}=30.06$

Work Step by Step

By using the table, the z-score corresponding to 0.01 and 0.99: $z_{1}=-2.33.$ $z_{2}=2.33$ Hence the corresponding values:$mean+z_{1}⋅standard \ deviation=24−2.33⋅2.6=17.94.$ $mean+z_{2}⋅standard \ deviation=24+2.33⋅2.6=30.06.$ These limits can be useful to keep the number of chocolate chips within a certain limit.
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