Answer
a) 0.6
b)0.5488
c)16.46
d)quite close
Work Step by Step
a) The mean: $\frac{18}{30}=0.6.$
b)$P(X=0)=\frac{0.6^0\cdot e^{-0.6}}{0!}=0.5488.$
c) Expected number:$30\cdot 0.5488=16.46.$
d)The expected number is quite close to the actual number.
