Elementary Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321836960
ISBN 13: 978-0-32183-696-0

Chapter 5 - Discrete Probability Distributions - 5-5 Poisson Probability Distributions - Basic Skills and Concepts - Page 233: 12

Answer

a)0.00005 b)0.0005 c)0.0027 d)0.0087 e)0.021

Work Step by Step

The mean of the deaths:$\frac{196}{20}=9..8$ By using the formula: a)$P(X=0)=\frac{9.8^0\cdot e^{-9.8}}{0!}=0.00005.$ b)$P(X=1)=\frac{9.8^1\cdot e^{-9.8}}{1!}=0.0005.$ c)$P(X=2)=\frac{9.8^2\cdot e^{-9.8}}{2!}=0.0027.$ d)$P(X=3)=\frac{9.8^3\cdot e^{-9.8}}{3!}=0.0087.$ e)$P(X=4)=\frac{9.8^4\cdot e^{-9.8}}{4!}=0.021.$
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