Elementary Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321836960
ISBN 13: 978-0-32183-696-0

Chapter 5 - Discrete Probability Distributions - 5-4 Parameters for Binomial Distributions - Beyond the Basics: 23

Answer

Mean:3, standard deviation:1.27.

Work Step by Step

Here, n=12, K=10, N=40. In a hypergeometric distribution the mean can be counted by: $n \cdot \frac{K}{N}=12 \cdot \frac{10}{40}=3.$ In a hypergeometric distribution the variance can be counted by: $n \cdot \frac{K}{N} \cdot \frac{N-K}{N} \cdot \frac{N-n}{N-1}=12 \cdot \frac{10}{40} \cdot \frac{30}{40} \cdot \frac{28}{39}=1.615.$ The standard deviation is the square root of the variance: $\sqrt {1.615}=1.27.$
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