Answer
Mean:668.58. Standard deviation:15.08. Minimum usual value:638.42, maximum usual value:698.74.
Work Step by Step
Mean=$n\cdot p=1013 \cdot 0.66=668.58$.
Standard deviation: $\sqrt{n \cdot p \cdot (1-p)}=\sqrt{1013 \cdot 0.66 \cdot 0.34}=15.08.$
If a value is unusual, then it is more than two standard deviations far from the mean. $Minimum \ usual \ value=mean-2\cdot(standard \ deviation)=668.58-2\cdot15.08=638.42$
$Maximum \ usual \ value=mean+2\cdot(standard \ deviation)=668.58+2\cdot15.08=698.74$.