Elementary Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321836960
ISBN 13: 978-0-32183-696-0

Chapter 5 - Discrete Probability Distributions - 5-3 Binomial Probability Distributions - Beyond the Basics - Page 222: 47

Answer

a) 0.000969 b)$7.15 \cdot 10^{-8}$ c) 0.436

Work Step by Step

By the given formula: a)$P=\frac{{6 \choose 4} \cdot {43 \choose 2}}{{49 \choose 6}}=0.000969$ b)$P=\frac{{6 \choose 6} \cdot {43 \choose 0}}{{49 \choose 6}}=7.15 \cdot 10^{-8}$ c)$P=\frac{{6 \choose 0} \cdot {43 \choose 6}}{{49 \choose 6}}=0.436$
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