Elementary Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321836960
ISBN 13: 978-0-32183-696-0

Chapter 5 - Discrete Probability Distributions - 5-2 Probability Distributions - Basic Skills and Concepts - Page 207: 11

Answer

Probability distribution, mean:2.2, standard deviation:1.

Work Step by Step

It is a probability distribution because $\sum P(x)=0.041+0.2+0.367+0.299+0.092\approx1$. Mean $0\cdot0.041+1\cdot0.2+2\cdot0.367+3\cdot0.299+4\cdot0.092=2.2$. Standard deviation: $\sqrt{(0-2.2)^2\cdot0.041+(1-2.2)^2 \cdot0.2+(2-2.2)^2\cdot0.367+(3-2.2)^2\cdot0.299+(4-2.2)^2\cdot0.092}=1$.
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