Elementary Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321836960
ISBN 13: 978-0-32183-696-0

Chapter 4 - Probability - Review - Review Exercises: 16

Answer

$\frac{1}{575,757}$

Work Step by Step

Because the order is not important, we can use the combination rule to determine the number of possibilities: $\frac{39!}{(39-5)!5!}=575,757$. We also know that $probability=\frac{number \ of \ good \ outcomes}{number\ of\ all\ outcomes}$, therefore $P(success)=\frac{1}{575,757}$.
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