Answer
Probably no, $0.0211$.
Work Step by Step
By using the complement rule:
$P(at \ least \ one \ positive)=1-P(no \ positive)=1-(1-\frac{213}{100,000})^{10}=1-(\frac{99,787}{100,000})^{10}\approx0.0211$. This is very close to 0, therefore the combined test samples probably won't be positive.
