Answer
Variance:0.83
Standard deviation:0.91
Range:3.
Work Step by Step
By using the results from before: $\mu=1.88.$
Variance=$\frac{\sum (x-\mu)^2}{n}=\frac{(2-1.88)^2+(1-1.88)^2+...+(2-1.88)^2}{25}=0.83.$
Standard deviation=$\sqrt{variance}=\sqrt{0.83}=0.91$
Range=maximum value-minimum value=$4-1=3$.
