Elementary Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321836960
ISBN 13: 978-0-32183-696-0

Chapter 3 - Statistics for Describing, Exploring, and Comparing Data - 3-2 Measures of Center - Basic Skills and Concepts: 22

Answer

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Work Step by Step

The mean can be counted by summing all the data and dividing it by the number of data: Brinks as collection contractor: $\frac{1.3+1.5+1.3+1.5+1.4+1.7+1.8+1.7+1.7+1.6}{10}=1.55$, not Brinks as collection contractor: $\frac{2.2+1.9+1.5+1.6+1.5+1.7+1.9+1.6+1.6+1.8}{10}=1.73$. The median is the average of the 1 or 2 (here 2) middle data: Brinks as collection contractor:(1.5+1.6)/2=1.55, not Brinks as collection contractor:(1.6+1.7)/2=1.65. It does not show evidence because the mean of Brinks employees is less than the mean of not Brink employees.
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