Elementary Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321836960
ISBN 13: 978-0-32183-696-0

Chapter 3 - Statistics for Describing, Exploring, and Comparing Data - 3-2 Measures of Center - Basic Skills and Concepts - Page 91: 9

Answer

The mean is 16.357 million, mode:4,9 and 10 million, the median is 10 million, the midrange is 31 million.

Work Step by Step

The mean can be counted by summing all the data and dividing it by the number of data: $\frac{58+22+27+29+21+10+10+8+7+9+11+9+4+4}{14}=16.357$, the mean is 16.357 million. The mode is the data occuring the most times, which here are 4,9 and 10 million. The median is the average of the 1 or 2 (here 2) middle data: (10+10)/2=01, the median is 10 million. The midrange is the average of the highest and the lowest data: (4+58)/2=31, the midrange is 31 million. We cannot see any pattern, however the reason for the highest values being on those days could be because the second day was on a day when people don't go to cinema as much.
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