Elementary Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321836960
ISBN 13: 978-0-32183-696-0

Chapter 11 - Goodness-of-Fit and Contingency Tables - 11-3 Contingency Tables - Basic Skills and Concepts - Page 586: 3

Answer

2, 5.991

Work Step by Step

r:number of rows, c:number of columns, hence degree of freedom=$(c-1)(r-1)=(2-1)(3-1)=2.$ Using the table the critical value: $X_{0.05}^2=5.991.$
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