Fail to reject the null hypothesis.
Work Step by Step
The value of the test statistic: $X^2=6.6$. By using the table, the corresponding P-value: P=0.679. If the P-value is less than the significance level, then this means the rejection of the null hypothesis. Hence: P is more than $\alpha=0.05$, so we fail to reject the null hypothesis. Hence we can say that there is sufficient evidence to support that the last digits don't occur with the same frequency.