Applied Statistics and Probability for Engineers, 6th Edition

Published by Wiley
ISBN 10: 1118539710
ISBN 13: 978-1-11853-971-2

Chapter 2 - Section 2-3 - Addition Rules - Exercises - Page 38: 2-84

Answer

(a) 90% = 0.9 (b) 10% = 0.1

Work Step by Step

First, we must observe that the events are mutually exclusive. (a) P(sport) = P(contact sport) + P(noncontact sport) = 46% + 44% = 90% 0.46 + 0.44 = 0.9 (b) P(non sport) = 1 - P(sport) = 1 - 0.9 = 0.1
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