Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 9 - Section 9.4 - Vectors in Three Dimensions - 9.4 Exercises - Page 658: 40

Answer

$a_1 = 48.19°$ $a_2 = 109,47°$ $a_3 = 48.19°$

Work Step by Step

The direction angles are determined by the following formula: $\cos {a_x} = \frac{u_x}{|u|}$ (from the book) Given $u = <2, -1, 2>$ Thus $|u| = \sqrt{ 2^2 + (-1)^2 + (2)^2} = \sqrt{4 + 1 + 4} = \sqrt 9 = 3 $ $\cos a_1 = \frac{2}{3}$ $\cos a_2 = \frac{-1}{3}$ $\cos a_3 = \frac{2}{3}$ Solve for each angle. $a_1 = 48.19°$ $a_2 = 109,47°$ $a_3 = 48.19°$
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