Answer
$<3, 1, -2>$
$3i + j -2k$
Work Step by Step
The question asks to find the vector $-2u + 3v$ in component form and in terms of i, j, and k
Given $u = <0, -2, 1>$ and $v = <1, -1, 0>$
$-2u + 3v = -2<0, -2, 1> + 3<1, -1, 0>$
$ = <0 + 3, 4 - 3, -2 + 0> = <3, 1, -2>$
You can convert component form directly into the terms of i, j, and k:
$<3, 1, -2> = 3i + j -2k$
