Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 9 - Section 9.4 - Vectors in Three Dimensions - 9.4 Exercises - Page 658: 17

Answer

$i - 2k$ $i + 2j + 2k$ $3i + 3.5j + k$

Work Step by Step

The question asks for the vectors $ u + v$, $u - v$, and $3u - 0.5 v$ Given $u = i + j$ and $v = $ $u = <1, 1, 0>$ and $v = <0, -1, -2>$ $u + v = <1 + 0, 1 + (-1), 0 + (-2)> = <1, 0, -2> = i - 2k$ $u - v = <1 - 0, 1 - (-1), 0 - (-2)> = <1, 2, 2> = i + 2j + 2k$ $3u - 0.5v = 3<1, 1, 0> - 0.5 <0, -1, -2>$ $= <3 - 0, 3 - (-0.5), 0 - (-1)> = <3, 3.5, 1> = 3i + 3.5j + k$
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