Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 8 - Section 8.2 - Graphs of Polar Equations - 8.2 Exercises - Page 600: 22

Answer

$(x-1/2)^2 + y^2 = 1/4$ See graph below.

Work Step by Step

The question asks for a graph of the polar equation and to convert the equation into rectangular coordinates Given $r = \cos θ$ Table of Values: $(1, 0)$ $(0.5, \frac{\pi}{3})$ $(0, \frac{\pi}{2})$ $(-0.5, \frac{2\pi}{3})$ $(-1, \pi)$ $(-0.5, \frac{4\pi}{3})$ $(0, \frac{3\pi}{2})$ $(0.5, \frac{5\pi}{3})$ See graph below. To convert the equation into rectangular coordinates, the following equation can be used: $r^2 = x^2 + y^2$ $x = r \cos θ$ So $r = \cos θ$ $r^2 = r \cos θ$ $x^2 + y^2 = x$ $x^2 - x + y^2 = 0$ $x^2 - x + 1/4 + y^2= 0 + 1/4$ $(x-1/2)^2 + y^2 = 1/4$ Circle centered at (1/2, 0) with radius 1/2
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