Answer
$sin\theta=\frac{\sqrt2}{2}$
$cos\theta=\frac{\sqrt2}{2}$
$tan\theta=1$
$csc\theta=\sqrt2$
$sec\theta=\sqrt2$
Work Step by Step
To identify all the remaining trigonometric ratios we will use the trigonometric identities and according to those ratios we will determine angle degrees to graph the triangle.
Step by step, we will first identify one of the trigonometric identities and then calculate:
$cot\theta = \frac{cos\theta}{sin\theta} = 1$;
$sin\theta=cos\theta$; Which means that we have $45-45-90$ triangle(Also see the image)
So, $\theta=45°$
$sin45°=cos45°=\frac{1}{\sqrt{2}}=\frac{\sqrt2}{2}$
$tan\theta=\frac{sin\theta}{cos\theta}=\frac{\frac{\sqrt2}{2}}{\frac{\sqrt2}{2}}=\frac{\sqrt2}{2}\times\frac{2}{\sqrt2}=1$
$csc\theta=\frac{1}{sin\theta}=\frac{2}{\sqrt{2}}=\frac{2\sqrt{2}}{2}=\sqrt2$
$sec\theta=\frac{1}{cos\theta}=\frac{2}{\sqrt{2}}=\frac{2\sqrt{2}}{2}=\sqrt2$