Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 5 - Section 5.6 - Modeling Harmonic Motion - 5.6 Exercises - Page 458: 54

Answer

$E(t)=219.2 cos(200\pi t)$ and $RMS=219.2V$

Work Step by Step

Step 1. Identify the quantities as $f=100rps, V_{max}=310$, thus we get $\frac{\omega}{2\pi}=100$ which gives $\omega=200\pi$. The RMS voltage (see Example 6) is given by $\frac{V_{max}}{\sqrt 2}=\frac{310}{\sqrt 2}=219.2$ volt. Step 2. Model with a cosine function $E(t)=a\cdot cos(\omega t)$ where $a=RMS=219.2$ we have $E(t)=219.2 cos(200\pi t)$ (assuming t=0, E(0)=219.2V)
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.