Answer
VI
Work Step by Step
Questions 3 through 8 asks for a match with the function with one of the graphs labeled I - VI
Given $f(x) = \cot 4x$
$\cot 4x = \frac{1}{\tan 4x}$
At $x = \frac {\pi}{16}$, $\cot 4x = 1$
There is also an asymptote at $x = 0$
The only graph that has that point and asymptote is graph VI