Answer
II
Work Step by Step
Questions 3 through 8 asks for a match with the function with one of the graphs labeled I - VI
Given $f(x) = \tan (x + \frac{\pi}{4})$
There is a horizontal shift $\frac{\pi}{4}$ units to the left
Thus at $x = \frac{-\pi}{4}$, $y = 0$
The only graph that has that point is graph II