Answer
amplitude=1
period =$\pi$
graph (black):
.
Work Step by Step
See p. 424
For
$y=a\sin k(x-b),\ ,\quad y=a\cos k(x-b)$,
$(k>0)$
Amplitude: $|a|$, Period: $\displaystyle \frac{2\pi}{k}$,
Horizontal shift: $b$
------------------
$y=-\sin 2x$
$a=-1 , k=2, b=0$
So,
amplitude=$|-1|=1$
period =$\displaystyle \frac{2\pi}{2}=\pi$
To graph,
begin with $f(x)=\cos x,$ (red, dashed)
horizontally compress by factor 2, (green, dashed)
then reflect across the x-axis (black, solid line).