Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 5 - Section 5.2 - Trigonometric Functions of Real Numbers - 5.2 Exercises - Page 417: 27

Answer

$\sin{t} = -\frac{3}{5}$ $\cos{t} = -\frac{4}{5}$ $\tan{t} = \frac{4}{3}$

Work Step by Step

RECALL: For the terminal point P(x, y) on a unit circle, $\sin{t} = y, \cos{t} = x, \text{ and } \tan{t} = \frac{y}{x}, x\ne0$ Use the formulas above to obtain: $\sin{t} = -\frac{3}{5}$ $\cos{t} = -\frac{4}{5}$ $\tan{t} = \dfrac{-\frac{4}{5}}{-\frac{3}{5}} = -\dfrac{4}{5} \cdot \left(-\dfrac{5}{3}\right)=\dfrac{4}{3}$
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