Answer
$\sin{t} = -\frac{3}{5}$
$\cos{t} = -\frac{4}{5}$
$\tan{t} = \frac{4}{3}$
Work Step by Step
RECALL:
For the terminal point P(x, y) on a unit circle,
$\sin{t} = y, \cos{t} = x, \text{ and } \tan{t} = \frac{y}{x}, x\ne0$
Use the formulas above to obtain:
$\sin{t} = -\frac{3}{5}$
$\cos{t} = -\frac{4}{5}$
$\tan{t} = \dfrac{-\frac{4}{5}}{-\frac{3}{5}} = -\dfrac{4}{5} \cdot \left(-\dfrac{5}{3}\right)=\dfrac{4}{3}$