Answer
a) $\frac{\pi}{6}$
b) $(\frac{\sqrt 3}{2},-\frac{1}{2})$
Work Step by Step
a) $2\pi - \frac{11\pi}{6} = \frac{\pi}{6}$
b) $\frac{11\pi}{6}$ has the terminal point $(\frac{\sqrt 3}{2},-\frac{1}{2})$ on the unit circle
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