Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 4 - Section 4.7 - Logarithmic Scales - 4.7 Exercises - Page 385: 9

Answer

a. 5.494 b. 6.31 cm

Work Step by Step

Given the magnitude equation $M = \log \frac{I}{S}$ with $S = 10^-4$ and $I = 31.25$ a. Solve for M $M = \log \frac{31.25}{10^{-4}}$ $M = \log 31.25 + \log 10^{4} = 5.494$ b. Given M = 4.8, find the intensity $4.8 = \log \frac{I}{10^{-4}}$ $10^{4.8} = \frac{I}{10^{-4}}$ $I = 10^{0.8} = 6.31 cm$
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