Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 4 - Section 4.5 - Exponential and Logarithmic Functions - 4.5 Exercises - Page 368: 62

Answer

$x=3$ and $x=-2$

Work Step by Step

$\log_{2}(x^{2}-x-2)=2$ Write this equation in exponential form: $x^{2}-x-2=2^{2}$ $x^{2}-x-2=4$ Take the $4$ to the left side of the equation: $x^{2}-x-2-4=0$ $x^{2}-x-6=0$ Solve by factoring: $(x-3)(x+2)=0$ We get two solutions: $x=3$ and $x=-2$
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