## Precalculus: Mathematics for Calculus, 7th Edition

$Use$ $the$ $Change$ $of$ $Base$ $Formula$ $and$ $a$ $calculator$ $to$ $evaluate$ $the$ $logarithm$: $\log_3 16$ Apply the Change of Base Formula: $\log_x y$ = $\frac{\log y}{\log x}$ $\log_3 16$ = $\frac{\log 16}{\log 3}$ Use a calculator and round to the sixth decimal place $\approx$2.523719