## Precalculus: Mathematics for Calculus, 7th Edition

$\log_3 2$ +$\log_3 x$ - $\log_3 y$
$Expand$ $the$ $expression$: $\log_3 \frac{2x}{y}$ Apply the Third Law of Logarithms $\log_3 \frac{2x}{y}$ = $\log_3 2x$ - $\log_3 y$ Apply the First Law of Logarithms to $\log_3 2x$ $\log_3 (2\times x )$ = $\log_3 2$ +$\log_3 x$ $\log_3 2x$ - $\log_3 y$ = $\log_3 2$ +$\log_3 x$ - $\log_3 y$