Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 4 - Section 4.4 - Laws of Logarithms - 4.4 exercises: 33

Answer

$\log_3 2$ +$\log_3 x$ - $\log_3 y$

Work Step by Step

$Expand$ $the$ $expression$: $\log_3 \frac{2x}{y}$ Apply the Third Law of Logarithms $\log_3 \frac{2x}{y}$ = $\log_3 2x$ - $\log_3 y$ Apply the First Law of Logarithms to $\log_3 2x$ $\log_3 (2\times x )$ = $\log_3 2$ +$\log_3 x$ $\log_3 2x$ - $\log_3 y$ = $\log_3 2$ +$\log_3 x$ - $\log_3 y$
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