## Precalculus: Mathematics for Calculus, 7th Edition

$\log_2 A$ + 2$\log_2 B$
$Expand$ $the$ $expression$: $\log_2 (AB^2)$ Apply the First Law of Logarithms $\log_2 (A\times B^2)$ = $\log_2 A$ + $\log_2 B^2$ Apply the Third Law of Logarithms to $\log_2 B^2$ $\log_2 B^2$ = 2$\log_2 B$ $\log_2 A$ + $\log_2 B^2$ = $\log_2 A$ + 2$\log_2 B$