## Precalculus: Mathematics for Calculus, 7th Edition

$\log_3 100$ - $\log_3 18$ - $\log_3 50$ To keep it even we apply the Second Law of Logarithms to $\log_3 100$ - $\log_3 50$ $\log_3 \frac{100}{50}$ - $\log_3 18$ $\log_3 2$ - $\log_3 18$ Apply the Second Law of Logarithms again $\log_3 \frac{2}{18}$ $\log_3 \frac{1}{9}$ $\log_3 \frac{1}{3^2}$ Move the denominator to the numerator with a negative exponent $\log_3 3^{-2}$ = -2