Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 4 - Section 4.3 - Logarithmic Functions - 4.3 Exercises - Page 354: 101

Answer

$ID1=5.32$ $ID2=4.32$

Work Step by Step

Given $A=100mm,W1=5mm,W2=10mm$, we have $ID1=\frac{log(2\times100/5)}{log2}=5.32$ $ID2=\frac{log(2\times100/10)}{log2}=4.32$
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