Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 4 - Section 4.3 - Logarithmic Functions - 4.3 Exercises - Page 353: 85

Answer

$ f\circ g(x)=2^{x+1},\qquad(-\infty,+\infty$) $ g\circ f(x)=2^{x}+1,\qquad(-\infty,+\infty$)

Work Step by Step

$f\circ g(x)=f(g(x))=2^{g(x)}=2^{x+1},$ no restriction,defined for all reals domain=$\mathbb{R}=(-\infty,+\infty$) $g\circ f(x)=g(f(x)=f(x)+1=2^{x}+1$ no restriction,defined for all reals domain=$\mathbb{R}=(-\infty,+\infty$)
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